Saturday, December 28, 2024

mining concept – The best way to create coinbase? The best way to use witness?

BIP141 provides a brand new rule referred to as “witness dedication”. The doc says: “The dedication is recorded in a scriptPubKey of the coinbase transaction.” I did not fairly perceive what that meant, Due to this fact, I immediately positioned the ‘default_witness_commitment’ supplied by the block template within the scriptPubKey location when creating coinbase. Here is my code:

def makeCoinbase()->None:
    world coinbase,tmpl
    model=pack('<L',1)
    inputCount=unhexlify('01')
    txHash=unhexlify('0000000000000000000000000000000000000000000000000000000000000000')
    preSequence=unhexlify('ffffffff')
    eh=encodeHeight(tmpl['height'])  #Don't be concerned about this perform, it handles peak
    msg=eh+b'my message'
    msgSize=pack('B',len(msg))
    sequence=unhexlify('ffffffff')
    outCount=unhexlify('01')
    quantity=pack('<Q',tmpl['coinbasevalue'])
    script=unhexlify(tmpl['default_witness_commitment'])
    scriptSize=pack('B',len(script))
    lockTime=unhexlify('00000000')
    coinbase=model+inputCount+txHash+preSequence+msgSize+msg+
        sequence+outCount+quantity+scriptSize+script+lockTime
    tmpl['transactions'].insert(0,{
        'knowledge':coinbase.hex(),
        'txid':dblsha(coinbase)[::-1].hex()
    })

The variable tmpl is the template obtained utilizing the “getblocktemplate” command.I am testing my code in regtest. After I submit a block, Bitcoin Core does create a brand new block. And my steadiness did go up.
Nonetheless, after I checked coinbases within the newly generated block, the outcome was as follows:

{
    'txid': '9cb794f3292d1ece3af6c1d3055cf6fb26cf2126ff48b39b229bfec5ec651ec4', 
    'hash': 'de081b2a9552ac559d3501ed0669f675530fe9890e27d263c1aff65e678ddc4e', 
    'model': 1, 
    'dimension': 153, 
    'vsize': 126, 
    'weight': 504, 
    'locktime': 0, 
    'vin': [{
        'coinbase': '016c54686520477265617420476f642050616e', 
        'txinwitness': ['0000000000000000000000000000000000000000000000000000000000000000'], 
        'sequence': 4294967295}], 
    'vout': [{
        'value': Decimal('50.00063100'), 
        'n': 0, 
        'scriptPubKey': {
            'asm': 'OP_RETURN aa21a9edb14717ddf39dacad0babfff4d8d951c076e95d11d2b1f328632c32f98c015d2c', 
            'desc': 'raw(6a24aa21a9edb14717ddf39dacad0babfff4d8d951c076e95d11d2b1f328632c32f98c015d2c)#psf60z3m', 
            'hex': '6a24aa21a9edb14717ddf39dacad0babfff4d8d951c076e95d11d2b1f328632c32f98c015d2c', 
            'type': 'nulldata'
        }
    }], 
    'hex': '010000000001010000000000000000000000000000000000000000000000000000000000000000ffffffff13016c54686520477265617420476f642050616effffffff017ce8062a01000000266a24aa21a9edb14717ddf39dacad0babfff4d8d951c076e95d11d2b1f328632c32f98c015d2c0120000000000000000000000000000000000000000000000000000000000000000000000000'
}

As you possibly can see, it accommodates just one vout. And that vout doesn’t comprise handle. However I have a look at coinbase for blocks in the principle community, and it all the time accommodates multiple vout, and the vout accommodates the handle.My query is am I constructing coinbase the precise method? If not, how do I repair it? Though the Bitcoin core didn’t report errors, I all the time suspected that I had misplaced the miner’s handle.

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