For each eventualities that I’ll describe under, assume the two issues.
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that community propagation for blocks at all times 6 seconds.
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that we begin taking a look at my evaluation from time = t0 and at that t0, each node has the identical actual chain.
State of affairs 1: block time = 10 min
If block time is 10 min and minerA solves blockD at time t0 + T, and shares it immediatelly, in the course of the time t0+T and t0+T+6, others miners may resolve their very own block that they have been engaged on. Let’s name the variable what number of miners resolve it throughout this time to be “X”
State of affairs 2: block time = 4 min
If block time is 4 min and minerA solves blockD at time t0 + T, and shares it immediatelly, in the course of the time t0+T and t0+T+4, others miners may resolve their very own block that they have been engaged on. Let’s name the variable what number of miners resolve it throughout this time to be “Y”
Because it seems, Y > X.
Query 1: Am I proper that Y can be larger than X ? ofc, not in 100% instances, however when it comes to chance.
Query 2: How do I make myself positive that it is mathematically true that Y > X ? I do know it should be about how difficulties and goal are set. It looks as if the much less problem, The upper the prospect to resolve a block throughout ANY 6 second interval. (NOTE the phrase: “ANY”). That is necessary as a result of we do not know precisely when minerA solves the block, however as I’ve learn, chance that Y > X is true for ANY 6 second interval, and this 6 second interval does not need to be nearer to 4 minutes or 10 minutes or no matter it’s. What can be a mathematical strategy to this so I consider on this ?
